What is (\partial)/(\partial x)(-2tan(x)sin(2y)) ?

The answer to (\partial)/(\partial x)(-2tan(x)sin(2y)) is -2sin(2y)sec^2(x)

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(\partial)/(\partial x)(-2tan(x)sin(2y))

\frac{\partial}{\partial x} (- 2 tan (x) sin (2 y))

- 2 sin (2 y) sec^{2} (x)

Solution steps

\frac{\partial}{\partial x} (- 2 tan (x) sin (2 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 sin (2 y) \frac{\partial}{\partial x} (tan (x))

Apply the common derivative:

\frac{\partial}{\partial x} (tan (x)) = sec^{2} (x)

= - 2 sin (2 y) sec^{2} (x)

\frac{d}{d x} (- A e^{- x})

\frac{d}{d x} (\frac{3 x}{2 x - 1})

\frac{d}{d x} (ln (g (x) (3 x^{2})))

\frac{d}{d x} (e^{2 x} sin (x))

\int \frac{y}{( y + 5 ) ( 2 y - 1 )} d y

What is (\partial)/(\partial x)(-2tan(x)sin(2y)) ?
The answer to (\partial)/(\partial x)(-2tan(x)sin(2y)) is -2sin(2y)sec^2(x)