What is the derivative of yx^2 ?

The derivative of yx^2 is (dy)/(dx)x^2+2xy

What is the first derivative of yx^2 ?

The first derivative of yx^2 is (dy)/(dx)x^2+2xy

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (y x^{2})

\frac{d y}{d x} x^{2} + 2 x y

Solution steps

\frac{d}{d x} (y x^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = y, g = x^{2}

= \frac{d y}{d x} x^{2} + \frac{d}{d x} (x^{2}) y

\frac{d}{d x} (x^{2}) = 2 x

= \frac{d y}{d x} x^{2} + 2 x y

\frac{\partial}{\partial x} (sin (- x) cos (2 y))

x \to 0 lim (\frac{ln ( 3 x + 1 )}{x})

19 - x^{2}

\frac{\partial}{\partial x} (ln (x^{2} + y^{2}))

y^{^{''}} = 4 y

What is the derivative of yx^2 ?
The derivative of yx^2 is (dy)/(dx)x^2+2xy
What is the first derivative of yx^2 ?
The first derivative of yx^2 is (dy)/(dx)x^2+2xy