What is (\partial)/(\partial x)(7xy^2+1) ?

The answer to (\partial)/(\partial x)(7xy^2+1) is 7y^2

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(\partial)/(\partial x)(7xy^2+1)

\frac{\partial}{\partial x} (7 x y^{2} + 1)

7 y^{2}

Solution steps

\frac{\partial}{\partial x} (7 x y^{2} + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (7 x y^{2}) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (7 x y^{2}) = 7 y^{2}

\frac{\partial}{\partial x} (1) = 0

= 7 y^{2} + 0

Simplify

= 7 y^{2}

\frac{d}{d x} (4 ln (2 x))

x \to 0 lim ((1 + 5 x)^{\frac{3}{x}})

\frac{( x ^{4} + 2 )}{ln ( x )}

\frac{\partial}{\partial x} (e^{- x y})

What is (\partial)/(\partial x)(7xy^2+1) ?
The answer to (\partial)/(\partial x)(7xy^2+1) is 7y^2