What is (\partial)/(\partial x)(x^2-3y^2) ?

The answer to (\partial)/(\partial x)(x^2-3y^2) is 2x

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(\partial)/(\partial x)(x^2-3y^2)

\frac{\partial}{\partial x} (x^{2} - 3 y^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} - 3 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (3 y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (3 y^{2}) = 0

= 2 x - 0

Simplify

= 2 x

\int_{0}^{1} \frac{54}{4 y - 1} d y

g (t) = arcsin (2 t)

\frac{\partial}{\partial x} (8 e^{x y + 7})

5 e^{5 e^{x} + x}

\frac{d}{d x} (3 x + \frac{1}{x})

What is (\partial)/(\partial x)(x^2-3y^2) ?
The answer to (\partial)/(\partial x)(x^2-3y^2) is 2x