What is the solution for (d^2y)/(dx^2)-6(dy)/(dx)+9y=0 ?

The solution for (d^2y)/(dx^2)-6(dy)/(dx)+9y=0 is y=c_{1}e^{3x}+c_{2}xe^{3x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)-6(dy)/(dx)+9y=0

\frac{d ^{2} y}{d x ^{2}} - 6 \frac{d y}{d x} + 9 y = 0

y = c_{1} e^{3 x} + c_{2} x e^{3 x}

Solution steps

\frac{d ^{2} y}{d x ^{2}} - 6 \frac{d y}{d x} + 9 y = 0

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} x e^{3 x}

y = c_{1} e^{3 x} + c_{2} x e^{3 x}

\frac{e ^{x}}{x + 4}

\frac{d}{d x} (x^{3} + x^{2} - 8 x + 7)

\int 2^{u} d u

\frac{d y}{d x} = \frac{( y ^{2} - 1 )}{x ^{2} - 1}, y (2) = 2

y^{^{''}} - y^{^{'}} + 289 y = 17 sin (17 t)

What is the solution for (d^2y)/(dx^2)-6(dy)/(dx)+9y=0 ?
The solution for (d^2y)/(dx^2)-6(dy)/(dx)+9y=0 is y=c_{1}e^{3x}+c_{2}xe^{3x}