What is the extreme f(x)=y^2-xy ?

The extreme f(x)=y^2-xy is Saddle(0,0)

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extreme f(x)=y^2-xy

extreme points

f (x) = y^{2} - x y

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

\int x^{2} (x - 2) d x

n = 0 \sum \infty \frac{n !}{10 3 ^{n}}

\frac{\partial}{\partial y} (x^{2} + 2 x y^{2} + 2 y^{2})

f (x) = x^{3} - \frac{3}{2} x^{2}

y = 2 - ∣ x ∣, y = x^{2}