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Popular >

y^'+2ty=5t

Solution

y^{^{'}} + 2 t y = 5 t

Solution

y = \frac{e ^{- t^{2} + c_{1}}}{2} + \frac{5}{2}

Solution steps

y^{'} (t) + 2 t y = 5 t

Solve separable ODE:

y = \frac{e ^{- t^{2} + c_{1}}}{2} + \frac{5}{2}

y = \frac{e ^{- t^{2} + c_{1}}}{2} + \frac{5}{2}

Popular Examples

area y=x^2,y=18-x^2 area

y = x^{2}, y = 18 - x^{2}

area y=x^2,x=3 area

y = x^{2}, x = 3

limit as (x,y) approaches (0,0) of (x^2+y^2)/(9+y^2)

(x, y) \to (0, 0) lim (\frac{x ^{2} + y ^{2}}{9 + y ^{2}})

5(dy)/(dx)-15x^2=0

5 \frac{d y}{d x} - 15 x^{2} = 0

derivative of y=x^2e^x-2xe^x+2e^x derivative of

y = x^{2} e^{x} - 2 x e^{x} + 2 e^{x}

Frequently Asked Questions (FAQ)

What is the solution for y^'+2ty=5t ?
The solution for y^'+2ty=5t is y=(e^{-t^2+c_{1}})/2+5/2