What is the derivative of y=x^2e^x-2xe^x+2e^x ?

The derivative of y=x^2e^x-2xe^x+2e^x is e^xx^2

What is the first derivative of y=x^2e^x-2xe^x+2e^x ?

The first derivative of y=x^2e^x-2xe^x+2e^x is e^xx^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

y = x^{2} e^{x} - 2 x e^{x} + 2 e^{x}

e^{x} x^{2}

Solution steps

\frac{d}{d x} (x^{2} e^{x} - 2 x e^{x} + 2 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} e^{x}) - \frac{d}{d x} (2 x e^{x}) + \frac{d}{d x} (2 e^{x})

\frac{d}{d x} (x^{2} e^{x}) = 2 x e^{x} + e^{x} x^{2}

\frac{d}{d x} (2 x e^{x}) = 2 (e^{x} + e^{x} x)

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

= 2 x e^{x} + e^{x} x^{2} - 2 (e^{x} + e^{x} x) + 2 e^{x}

Simplify

2 x e^{x} + e^{x} x^{2} - 2 (e^{x} + e^{x} x) + 2 e^{x} : e^{x} x^{2}

= e^{x} x^{2}

e^{2 y} y^{^{'}} = 1 - e^{2 y}

y = \frac{3}{x}, y = 4 - x

n = 0 \sum \infty (\frac{2}{9})^{n}

(1, 4), (- 9, - 10)

\int p^{6} ln (p) d p

What is the derivative of y=x^2e^x-2xe^x+2e^x ?
The derivative of y=x^2e^x-2xe^x+2e^x is e^xx^2
What is the first derivative of y=x^2e^x-2xe^x+2e^x ?
The first derivative of y=x^2e^x-2xe^x+2e^x is e^xx^2