What is the integral of p^6ln(p) ?

The integral of p^6ln(p) is 1/7 p^7ln(p)-(p^7)/(49)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of p^6ln(p)

\int p^{6} ln (p) d p

\frac{1}{7} p^{7} ln (p) - \frac{p ^{7}}{49} + C

Solution steps

\int p^{6} ln (p) d p

Apply Integration By Parts

: \frac{1}{7} p^{7} ln (p) - \int \frac{p ^{6}}{7} d p

= \frac{1}{7} p^{7} ln (p) - \int \frac{p ^{6}}{7} d p

\int \frac{p ^{6}}{7} d p = \frac{p ^{7}}{49}

= \frac{1}{7} p^{7} ln (p) - \frac{p ^{7}}{49}

Add a constant to the solution

= \frac{1}{7} p^{7} ln (p) - \frac{p ^{7}}{49} + C

\frac{1}{x ^{9}}

4 cos (x^{2}) - 8 x^{2} sin (x^{2})

\int_{0}^{4} 1 + \frac{9}{4} x d x

\int_{0}^{6} 3 4 x + 1 d x

\int \frac{1}{x 6 x + 4} d x

What is the integral of p^6ln(p) ?
The integral of p^6ln(p) is 1/7 p^7ln(p)-(p^7)/(49)+C