What is the solution for y^'+2y=3e^{2x} ?

The solution for y^'+2y=3e^{2x} is y=(3e^{2x})/4+(c_{1})/(e^{2x)}

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y^'+2y=3e^{2x}

y^{^{'}} + 2 y = 3 e^{2 x}

y = \frac{3 e ^{2 x}}{4} + \frac{c _{1}}{e ^{2 x}}

Solution steps

y^{'} (x) + 2 y = 3 e^{2 x}

Solve linear ODE:

y = \frac{3 e ^{2 x}}{4} + \frac{c _{1}}{e ^{2 x}}

y = \frac{3 e ^{2 x}}{4} + \frac{c _{1}}{e ^{2 x}}

\int_{0}^{4} 2 π (x) (4 x - x^{2}) d x

\frac{d}{d x} (\frac{1}{x ^{- 5}})

2 \times 2 + 6 \times 1/22 \times 2

\frac{\partial}{\partial x} (y^{- 2} (4 y + 9 x^{2}))

f (x) = (x^{3} + x)^{6}

What is the solution for y^'+2y=3e^{2x} ?
The solution for y^'+2y=3e^{2x} is y=(3e^{2x})/4+(c_{1})/(e^{2x)}