What is the derivative of f(x)=(x^3+x)^6 ?

The derivative of f(x)=(x^3+x)^6 is 6(x^3+x)^5(3x^2+1)

What is the first derivative of f(x)=(x^3+x)^6 ?

The first derivative of f(x)=(x^3+x)^6 is 6(x^3+x)^5(3x^2+1)

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derivative of

f (x) = (x^{3} + x)^{6}

6 (x^{3} + x)^{5} (3 x^{2} + 1)

Solution steps

\frac{d}{d x} ((x^{3} + x)^{6})

Apply the chain rule:

6 (x^{3} + x)^{5} \frac{d}{d x} (x^{3} + x)

= 6 (x^{3} + x)^{5} \frac{d}{d x} (x^{3} + x)

\frac{d}{d x} (x^{3} + x) = 3 x^{2} + 1

= 6 (x^{3} + x)^{5} (3 x^{2} + 1)

\frac{\partial}{\partial x} (sin (3 t))

f (x) = cos (x^{4})

\frac{\partial}{\partial s} (\frac{( r + s )}{t})

y = 7 ln (\frac{e ^{x} + e ^{- x}}{2}), (0, 0)

\frac{d}{d x} ((x^{2} - 2 x + 2) e^{x})

What is the derivative of f(x)=(x^3+x)^6 ?
The derivative of f(x)=(x^3+x)^6 is 6(x^3+x)^5(3x^2+1)
What is the first derivative of f(x)=(x^3+x)^6 ?
The first derivative of f(x)=(x^3+x)^6 is 6(x^3+x)^5(3x^2+1)