What is (\partial}{\partial s}(\frac{(r+s))/t) ?

The answer to (\partial}{\partial s}(\frac{(r+s))/t) is 1/t

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(\partial}{\partial s}(\frac{(r+s))/t)

\frac{\partial}{\partial s} (\frac{( r + s )}{t})

\frac{1}{t}

Solution steps

\frac{\partial}{\partial s} (\frac{( r + s )}{t})

Treat

r, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{t} \frac{\partial}{\partial s} (r + s)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{t} (\frac{\partial}{\partial s} (r) + \frac{\partial}{\partial s} (s))

\frac{\partial}{\partial s} (r) = 0

\frac{\partial}{\partial s} (s) = 1

= \frac{1}{t} (0 + 1)

Simplify

= \frac{1}{t}

y = 7 ln (\frac{e ^{x} + e ^{- x}}{2}), (0, 0)

\frac{d}{d x} ((x^{2} - 2 x + 2) e^{x})

\int 15 x + \frac{3}{x} d x

y = x^{2} + 2 x + 1

x \frac{d y}{d x} = y^{2} + 1

What is (\partial}{\partial s}(\frac{(r+s))/t) ?
The answer to (\partial}{\partial s}(\frac{(r+s))/t) is 1/t