What is the integral of (sin(20t))/(sin(10t)) ?

The integral of (sin(20t))/(sin(10t)) is xsin(20t)csc(10t)+C

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integral of (sin(20t))/(sin(10t))

\int \frac{sin ( 20 t )}{sin ( 10 t )} d x

x sin (20 t) csc (10 t) + C

Solution steps

\int \frac{sin ( 20 t )}{sin ( 10 t )} d x

Integral of a constant:

\int a d x = a x

= \frac{sin ( 20 t )}{sin ( 10 t )} x

Use the basic trigonometric identity:

\frac{1}{sin ( x )} = csc (x)

= x sin (20 t) csc (10 t)

Add a constant to the solution

= x sin (20 t) csc (10 t) + C

\int (3 t + 8)^{2.8} d t

\int 3 x^{5} - 5 x^{9} d x

d y = 2 t (y^{2} + 9) d t

n = 1 \sum \infty \frac{1}{n ^{\frac{4}{3}}}

\frac{\partial}{\partial x} (3 x + 6 y)

What is the integral of (sin(20t))/(sin(10t)) ?
The integral of (sin(20t))/(sin(10t)) is xsin(20t)csc(10t)+C