What is the integral from-2 to 1 of sqrt(1+(-3)^2) ?

The integral from-2 to 1 of sqrt(1+(-3)^2) is 3sqrt(10)

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integral from-2 to 1 of sqrt(1+(-3)^2)

\int_{- 2}^{1} 1 + (- 3)^{2} d x

310

Decimal Notation

9.48683 \dots

Solution steps

\int_{- 2}^{1} 1 + (- 3)^{2} d x

Integral of a constant:

\int a d x = a x

= [1 + (- 3)^{2} x]_{- 2}^{1}

1 + (- 3)^{2} = 10

= [10 x]_{- 2}^{1}

Compute the boundaries:

310

= 310

\int cos^{2} (x) sin^{4} (x) d x

\int e^{- s x} \cdot x^{2} d x

- x^{2} + 9 x + 3, at x = 5

y = x^{2}, y = x, y = 0

n = 2 \sum \infty e^{3 - 4 n}

What is the integral from-2 to 1 of sqrt(1+(-3)^2) ?
The integral from-2 to 1 of sqrt(1+(-3)^2) is 3sqrt(10)