What is the limit as x approaches infinity of 1/x-3 ?

The limit as x approaches infinity of 1/x-3 is -3

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limit as x approaches infinity of 1/x-3

x \to \infty lim (\frac{1}{x} - 3)

- 3

Solution steps

x \to \infty lim (\frac{1}{x} - 3)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (\frac{1}{x}) - x \to \infty lim (3)

x \to \infty lim (\frac{1}{x}) = 0

x \to \infty lim (3) = 3

= 0 - 3

Simplify

= - 3

\frac{d}{d x} (\frac{7 x ^{2}}{x})

\int_{0}^{1} 9 (x^{2} + 1) e^{- x} d x

\int \frac{x}{2 x + 3} d x

\int x^{3} e^{9 x} d x

y = 10 x^{4} - 10 x^{2}, y = 7 x^{2}

What is the limit as x approaches infinity of 1/x-3 ?
The limit as x approaches infinity of 1/x-3 is -3