What is the solution for x^2y^{''}+4xy^'+2y=0 ?

The solution for x^2y^{''}+4xy^'+2y=0 is y=(c_{1})/x+(c_{2})/(x^2)

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x^2y^{''}+4xy^'+2y=0

x^{2} y^{^{''}} + 4 x y^{^{'}} + 2 y = 0

y = \frac{c _{1}}{x} + \frac{c _{2}}{x ^{2}}

Solution steps

x^{2} y^{''} (x) + 4 x y^{'} (x) + 2 y = 0

Solve linear ODE:

y = \frac{c _{1}}{x} + \frac{c _{2}}{x ^{2}}

y = \frac{c _{1}}{x} + \frac{c _{2}}{x ^{2}}

x \to 8 lim (x + 8)

x \to \infty lim (ln (2))

\frac{( 3 s - 17 )}{s ^{2} - 2 s - 3}

n = 0 \sum \infty (\frac{2}{e})^{n}

(x^{2} + 4)^{5}

What is the solution for x^2y^{''}+4xy^'+2y=0 ?
The solution for x^2y^{''}+4xy^'+2y=0 is y=(c_{1})/x+(c_{2})/(x^2)