What is the derivative of f(x)=(3x-4)^2 ?

The derivative of f(x)=(3x-4)^2 is 6(3x-4)

What is the first derivative of f(x)=(3x-4)^2 ?

The first derivative of f(x)=(3x-4)^2 is 6(3x-4)

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derivative of

f (x) = (3 x - 4)^{2}

6 (3 x - 4)

Solution steps

\frac{d}{d x} ((3 x - 4)^{2})

Apply the chain rule:

2 (3 x - 4) \frac{d}{d x} (3 x - 4)

= 2 (3 x - 4) \frac{d}{d x} (3 x - 4)

\frac{d}{d x} (3 x - 4) = 3

= 2 (3 x - 4) \cdot 3

Simplify

= 6 (3 x - 4)

y^{^{''}} + 2 y^{^{'}} = 2 x + 3 - e^{- 2 x}

\frac{d r}{d θ} + r tan (θ) = 5 sec (θ)

\int \frac{\frac{1}{2}}{4 - 3 x ^{2}} d x

\int arcsec (y) d y

\int sec^{2} (θ) tan^{6} (θ) d θ

What is the derivative of f(x)=(3x-4)^2 ?
The derivative of f(x)=(3x-4)^2 is 6(3x-4)
What is the first derivative of f(x)=(3x-4)^2 ?
The first derivative of f(x)=(3x-4)^2 is 6(3x-4)