What is the first derivative of 2θ ?

The first derivative of 2θ is 2

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derivative of 2θ

derivative of

2 θ

2

Solution steps

\frac{d}{d θ} (2 θ)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d θ} (θ)

Apply the common derivative:

\frac{d}{d θ} (θ) = 1

= 2 \cdot 1

Simplify

= 2

\frac{d}{d x} (2 x^{2} sin (x) + 2 x cos (x))

\int x + 1 d x

\int sec^{2} (x) + sec (x) tan (x) d x

\int \frac{π}{2} (x + cos (x)) d x

\frac{d}{d x} (x^{2} - 4 x + 1)