What is the tangent of y= 1/(x-6),(-2,-1/8) ?

The tangent of y= 1/(x-6),(-2,-1/8) is y=-1/64 x-5/32

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tangent of y= 1/(x-6),(-2,-1/8)

tangent of

y = \frac{1}{x - 6}, (- 2, - \frac{1}{8})

y = - \frac{1}{64} x - \frac{5}{32}

Solution steps

Find the slope of

y = \frac{1}{x - 6} : \frac{d y}{d x} = - \frac{1}{( x - 6 ) ^{2}}

Compute the slope of

y = \frac{1}{x - 6}

(- 2, - \frac{1}{8}) : m = - \frac{1}{64}

Find the line with slope m=

- \frac{1}{64}

and passing through

(- 2, - \frac{1}{8}) : y = - \frac{1}{64} x - \frac{5}{32}

y = - \frac{1}{64} x - \frac{5}{32}

\int (2 x - 1)^{3} d x

\frac{d y}{d t} = t^{2} y^{3}

\frac{d}{d x} (x^{3} (3 x - 8))

\int_{6}^{11} 10 arccot (x) d x

f (x) = sin (sin (8 e^{x}))

What is the tangent of y= 1/(x-6),(-2,-1/8) ?
The tangent of y= 1/(x-6),(-2,-1/8) is y=-1/64 x-5/32