What is the derivative of x^3(3x-8) ?

The derivative of x^3(3x-8) is 12x^3-24x^2

What is the first derivative of x^3(3x-8) ?

The first derivative of x^3(3x-8) is 12x^3-24x^2

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\frac{d}{d x} (x^{3} (3 x - 8))

12 x^{3} - 24 x^{2}

Solution steps

\frac{d}{d x} (x^{3} (3 x - 8))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = 3 x - 8

= \frac{d}{d x} (x^{3}) (3 x - 8) + \frac{d}{d x} (3 x - 8) x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x - 8) = 3

= 3 x^{2} (3 x - 8) + 3 x^{3}

Simplify

3 x^{2} (3 x - 8) + 3 x^{3} : 12 x^{3} - 24 x^{2}

= 12 x^{3} - 24 x^{2}

\int_{6}^{11} 10 arccot (x) d x

f (x) = sin (sin (8 e^{x}))

\int \frac{1}{u ^{2} - a ^{2}} d u

x^{8} (x - 4)^{7}

\frac{d}{d x} (cos (2^{3 x^{2} + 5 x - 6}))

What is the derivative of x^3(3x-8) ?
The derivative of x^3(3x-8) is 12x^3-24x^2
What is the first derivative of x^3(3x-8) ?
The first derivative of x^3(3x-8) is 12x^3-24x^2