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Popular >

derivative of 1/(x^4+1/(x^2)-x^3)

Solution

\frac{d}{d x} (\frac{1}{x ^{4}} + \frac{1}{x ^{2}} - x^{3})

Solution

- \frac{4}{x ^{5}} - \frac{2}{x ^{3}} - 3 x^{2}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{4}} + \frac{1}{x ^{2}} - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x ^{4}}) + \frac{d}{d x} (\frac{1}{x ^{2}}) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (\frac{1}{x ^{4}}) = - \frac{4}{x ^{5}}

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

\frac{d}{d x} (x^{3}) = 3 x^{2}

= - \frac{4}{x ^{5}} - \frac{2}{x ^{3}} - 3 x^{2}

Popular Examples

integral of (x^2-5)^5*2x

\int (x^{2} - 5)^{5} \cdot 2 x d x

y^{^{''}} = x e^{x}

tangent of f(x)=x^3-2x^2+4x+3,\at x=1 tangent of

f (x) = x^{3} - 2 x^{2} + 4 x + 3, at x = 1

10x-8y*sqrt(x^2+1)(dy)/(dx)=0,y(0)=4

10 x - 8 y \cdot x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 4

derivative of f(x)=((x-5))/((x+3)^4)derivative of

f (x) = \frac{( x - 5 )}{( x + 3 ) ^{4}}

Frequently Asked Questions (FAQ)

What is the derivative of 1/(x^4+1/(x^2)-x^3) ?
The derivative of 1/(x^4+1/(x^2)-x^3) is -4/(x^5)-2/(x^3)-3x^2
What is the first derivative of 1/(x^4+1/(x^2)-x^3) ?
The first derivative of 1/(x^4+1/(x^2)-x^3) is -4/(x^5)-2/(x^3)-3x^2