What is the integral from 0 to 1 of x^{1/2} ?

The integral from 0 to 1 of x^{1/2} is 2/3

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integral from 0 to 1 of x^{1/2}

\int_{0}^{1} x^{\frac{1}{2}} d x

\frac{2}{3}

Decimal Notation

0.66666 \dots

Solution steps

\int_{0}^{1} x^{\frac{1}{2}} d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

= [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

Compute the boundaries:

\frac{2}{3}

= \frac{2}{3}

n = 1 \sum \infty \frac{1}{2 ^{n} n !}

x y^{^{'}} + y = 37 x

x \to 0 lim (\frac{4 ^{x} - 1 0 ^{x}}{x})

\frac{d}{d t} (1 + cos (t))

What is the integral from 0 to 1 of x^{1/2} ?
The integral from 0 to 1 of x^{1/2} is 2/3