What is the derivative of 6e^x+2/(\sqrt[3]{x}) ?

The derivative of 6e^x+2/(\sqrt[3]{x}) is 6e^x-2/(3x^{4/3)}

What is the first derivative of 6e^x+2/(\sqrt[3]{x}) ?

The first derivative of 6e^x+2/(\sqrt[3]{x}) is 6e^x-2/(3x^{4/3)}

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6 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (6 e^{x}) = 6 e^{x}

= 6 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

(3 t^{2})^{^{'}}

\frac{d y}{d x}, y = 4^{x}

\frac{d}{d x} (ln (x^{2} + 14 x + 55))

\frac{4 t}{4 + t}

x \to 4 lim (x + 4)

What is the derivative of 6e^x+2/(\sqrt[3]{x}) ?
The derivative of 6e^x+2/(\sqrt[3]{x}) is 6e^x-2/(3x^{4/3)}
What is the first derivative of 6e^x+2/(\sqrt[3]{x}) ?
The first derivative of 6e^x+2/(\sqrt[3]{x}) is 6e^x-2/(3x^{4/3)}