What is the solution for (dQ)/(dt)= 12/5-3Q ?

The solution for (dQ)/(dt)= 12/5-3Q is Q=-(e^{-3t-c_{1}})/(15)+4/5

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(dQ)/(dt)= 12/5-3Q

\frac{d Q}{d t} = \frac{12}{5} - 3 Q

Q = - \frac{e ^{- 3 t - c_{1}}}{15} + \frac{4}{5}

Solution steps

\frac{d Q}{d t} = \frac{12}{5} - 3 Q

Solve separable ODE:

Q = - \frac{e ^{- 3 t - c_{1}}}{15} + \frac{4}{5}

Q = - \frac{e ^{- 3 t - c_{1}}}{15} + \frac{4}{5}

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What is the solution for (dQ)/(dt)= 12/5-3Q ?
The solution for (dQ)/(dt)= 12/5-3Q is Q=-(e^{-3t-c_{1}})/(15)+4/5