What is (\partial)/(\partial x)(xe^{2t}-4x) ?

The answer to (\partial)/(\partial x)(xe^{2t}-4x) is e^{2t}-4

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(\partial)/(\partial x)(xe^{2t}-4x)

\frac{\partial}{\partial x} (x e^{2 t} - 4 x)

e^{2 t} - 4

Solution steps

\frac{\partial}{\partial x} (x e^{2 t} - 4 x)

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x e^{2 t}) - \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (x e^{2 t}) = e^{2 t}

\frac{\partial}{\partial x} (4 x) = 4

= e^{2 t} - 4

x, x - 2, 0

\frac{\partial}{\partial x} (ln (x^{2} - 4 x y + y^{2}))

f (x) = (ln (5))^{t}

x \to 0 lim (\frac{4}{17 + x})

\int \frac{1}{( x ^{2} + 9 )} d x

What is (\partial)/(\partial x)(xe^{2t}-4x) ?
The answer to (\partial)/(\partial x)(xe^{2t}-4x) is e^{2t}-4