What is the limit as x approaches 0 of 4/(17+x) ?

The limit as x approaches 0 of 4/(17+x) is 4/17

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limit as x approaches 0 of 4/(17+x)

x \to 0 lim (\frac{4}{17 + x})

\frac{4}{17}

Decimal Notation

0.23529 \dots

Solution steps

x \to 0 lim (\frac{4}{17 + x})

Plug in the value

x = 0

= \frac{4}{17 + 0}

Simplify

= \frac{4}{17}

\int \frac{1}{( x ^{2} + 9 )} d x

\frac{d}{d x} (x^{2} + x)

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{2}{x ^{4}}) (x + 8 x^{3}))

n = 1 \sum \infty (\frac{1}{2})^{\frac{1}{n}}

\int_{1}^{2} (x + \frac{1}{x})^{2} d x

What is the limit as x approaches 0 of 4/(17+x) ?
The limit as x approaches 0 of 4/(17+x) is 4/17