What is the tangent of sqrt(x),\at x=81 ?

The tangent of sqrt(x),\at x=81 is y= 1/18 x+9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of sqrt(x),\at x=81

tangent of

x, at x = 81

y = \frac{1}{18} x + \frac{9}{2}

Solution steps

Find the tangent point:

(81, 9)

Find the slope of

y = x : \frac{d y}{d x} = \frac{1}{2 x}

Compute the slope of

y = x

x = 81 : m = \frac{1}{18}

Find the line with slope m=

\frac{1}{18}

and passing through

(81, 9) : y = \frac{1}{18} x + \frac{9}{2}

y = \frac{1}{18} x + \frac{9}{2}

e^{r}

\int_{0}^{\frac{3 π}{2}} 3 ∣ sin (x) ∣ d x

(y^{3} - t^{3}) d t - t y^{2} d y = 0, y (1) = 3

f (x) = \frac{5 - 4 x ^{2} + x ^{5}}{x ^{3}}

\frac{d y}{d x} = 8 x 25 - y^{2}

What is the tangent of sqrt(x),\at x=81 ?
The tangent of sqrt(x),\at x=81 is y= 1/18 x+9/2