What is the solution for y^{''}+3y^'+2y=e^{-t},y(0)=0,y^'(0)=1 ?

The solution for y^{''}+3y^'+2y=e^{-t},y(0)=0,y^'(0)=1 is y=e^{-t}t

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y^{''}+3y^'+2y=e^{-t},y(0)=0,y^'(0)=1

y^{^{''}} + 3 y^{^{'}} + 2 y = e^{- t}, y (0) = 0, y^{^{'}} (0) = 1

y = e^{- t} t

Solution steps

y^{''} (t) + 3 y^{'} (t) + 2 y = e^{- t}

Solve linear ODE:

y = e^{- t} t

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What is the solution for y^{''}+3y^'+2y=e^{-t},y(0)=0,y^'(0)=1 ?
The solution for y^{''}+3y^'+2y=e^{-t},y(0)=0,y^'(0)=1 is y=e^{-t}t