What is inverse oflaplace 3/((s^2+9)) ?

The answer to inverse oflaplace 3/((s^2+9)) is sin(3t)

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inverse oflaplace 3/((s^2+9))

inverse laplace

\frac{3}{( s ^{2} + 9 )}

sin (3 t)

Solution steps

L^{- 1} {\frac{3}{( s ^{2} + 9 )}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s ^{2} + a ^{2}}} = sin (a t)

L^{- 1} {\frac{3}{s ^{2} + 3 ^{2}}} = sin (3 t)

= sin (3 t)

\frac{1}{x}, - 1

\int \frac{3 x ^{5}}{5 - 12 x ^{6}} d x

\int_{1}^{e} \frac{2}{x} d x

\int (- 1)^{n}

\frac{\partial}{\partial x} (tan (x^{2} + y^{2}))

What is inverse oflaplace 3/((s^2+9)) ?
The answer to inverse oflaplace 3/((s^2+9)) is sin(3t)