What is the integral from-2 to 3 of (46)/(x^4) ?

The integral from-2 to 3 of (46)/(x^4) is diverges

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integral from-2 to 3 of (46)/(x^4)

\int_{- 2}^{3} \frac{46}{x ^{4}} d x

diverges

Solution steps

\int_{- 2}^{3} \frac{46}{x ^{4}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 2}^{0} \frac{46}{x ^{4}} d x + \int_{0}^{3} \frac{46}{x ^{4}} d x

\int_{- 2}^{0} \frac{46}{x ^{4}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

x (- \frac{1}{5})

x \frac{d y}{d x} + 2 y = - 2 sin (x)

\int_{0}^{4} (5 x - x^{2}) - x d x

f (x) = 2 x^{2} e^{x}

\frac{d ^{2}}{d x ^{2}} (\frac{1}{1 + x})

What is the integral from-2 to 3 of (46)/(x^4) ?
The integral from-2 to 3 of (46)/(x^4) is diverges