What is the tangent of y=sqrt(x+225),(0,15) ?

The tangent of y=sqrt(x+225),(0,15) is y= 1/30 x+15

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tangent of y=sqrt(x+225),(0,15)

tangent of

y = x + 225, (0, 15)

y = \frac{1}{30} x + 15

Solution steps

Find the slope of

y = x + 225 : \frac{d y}{d x} = \frac{1}{2 x + 225}

Compute the slope of

y = x + 225

(0, 15) : m = \frac{1}{30}

Find the line with slope m=

\frac{1}{30}

and passing through

(0, 15) : y = \frac{1}{30} x + 15

y = \frac{1}{30} x + 15

\int 2 x^{2} - 2 d x

\frac{d}{d x} (\frac{1 - x ^{2}}{x})

\frac{d}{d x} (x^{2} - x^{3} + 3)

\int \frac{e ^{l n^{2} (x)}}{x} ln (x) d x

y = \frac{8}{x - 7}

What is the tangent of y=sqrt(x+225),(0,15) ?
The tangent of y=sqrt(x+225),(0,15) is y= 1/30 x+15