What is the limit as x approaches 1 of sin(3pix) ?

The limit as x approaches 1 of sin(3pix) is 0

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limit as x approaches 1 of sin(3pix)

x \to 1 lim (sin (3 π x))

0

Solution steps

x \to 1 lim (sin (3 π x))

Plug in the value

x = 1

= sin (3 π 1)

Simplify

sin (3 π 1) : 0

= 0

y + (x + 1) \frac{d y}{d x} = 2 x + 2, y (0) = 2

y^{^{'}} = - 8 x y

\frac{d y}{d x} = e^{2 x - y}

\int - e^{- x} ln (x) d x

(1 + x^{2}) (e^{2 t} d t - e^{x} d x) - (1 + x) d x = 0

What is the limit as x approaches 1 of sin(3pix) ?
The limit as x approaches 1 of sin(3pix) is 0