What is laplacetransform 8t ?

The answer to laplacetransform 8t is 8/(s^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 8t

laplace transform

8 t

\frac{8}{s ^{2}}

Solution steps

L {8 t}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 8 L {t}

L {t} : \frac{1}{s ^{2}}

= 8 \cdot \frac{1}{s ^{2}}

Refine

8 \frac{1}{s ^{2}} : \frac{8}{s ^{2}}

= \frac{8}{s ^{2}}

x^{2} - 6 x, - x^{2} + 4 x

f (t) = 3 t^{2} - t

\int \frac{2 x ^{2} + x + 1}{x ^{3} + 2 x ^{2} + x} d x

\frac{d}{d x} (x^{2} + 2 x)

y = (\frac{x ^{2} + 1}{x ^{2} - 1})^{6}