What is laplacetransform sin(t+pi/4) ?

The answer to laplacetransform sin(t+pi/4) is (s+1)/(sqrt(2)(s^2+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform sin(t+pi/4)

laplace transform

sin (t + \frac{π}{4})

\frac{s + 1}{2 ( s ^{2} + 1 )}

Solution steps

L {sin (t + \frac{π}{4})}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (t + \frac{π}{4})} = \frac{s sin ( \frac{π}{4} ) + 1 \cdot cos ( \frac{π}{4} )}{s ^{2} + 1 ^{2}}

= \frac{s sin ( \frac{π}{4} ) + 1 \cdot cos ( \frac{π}{4} )}{s ^{2} + 1 ^{2}}

= \frac{s + 1}{2 ( s ^{2} + 1 )}

\int_{0}^{1} (1 - x^{2})^{2} d x

(2 - x)^{^{'}}

\frac{d}{d x} (- 7 cos (x))

y = 6 x, y = 3 x^{2}

\int_{0}^{1} 9 x d x

What is laplacetransform sin(t+pi/4) ?
The answer to laplacetransform sin(t+pi/4) is (s+1)/(sqrt(2)(s^2+1))