What is the tangent of f(x)=sin(x)+cos(x),\at x=0 ?

The tangent of f(x)=sin(x)+cos(x),\at x=0 is y=x+1

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tangent of f(x)=sin(x)+cos(x),\at x=0

tangent of

f (x) = sin (x) + cos (x), at x = 0

y = x + 1

Solution steps

Find the tangent point:

(0, 1)

Find the slope of

f (x) = sin (x) + cos (x) : \frac{df ( x )}{d x} = cos (x) - sin (x)

Compute the slope of

f (x) = sin (x) + cos (x)

x = 0 : m = 1

Find the line with slope m=

1

and passing through

(0, 1) : y = x + 1

y = x + 1

\frac{d}{d x} (1 - x + ln (x))

\int_{0}^{a} e^{\frac{x}{a}} - e^{- \frac{x}{a}} d x

x = 6.4 sin (1. 2^{2} t^{2})

\frac{d}{d x} (ln (\frac{x}{5}))

What is the tangent of f(x)=sin(x)+cos(x),\at x=0 ?
The tangent of f(x)=sin(x)+cos(x),\at x=0 is y=x+1