What is (\partial ^2)/(\partial x\partial y)(x^5+x^2y+x+3) ?

The answer to (\partial ^2)/(\partial x\partial y)(x^5+x^2y+x+3) is 2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial ^2)/(\partial x\partial y)(x^5+x^2y+x+3)

\frac{\partial ^{2}}{\partial x \partial y} (x^{5} + x^{2} y + x + 3)

2 x

Solution steps

\frac{\partial ^{2}}{\partial x \partial y} (x^{5} + x^{2} y + x + 3)

\frac{\partial}{\partial x} (x^{5} + x^{2} y + x + 3) = 5 x^{4} + 2 x y + 1

= \frac{\partial}{\partial y} (5 x^{4} + 2 x y + 1)

\frac{\partial}{\partial y} (5 x^{4} + 2 x y + 1) = 2 x

= 2 x

- 7

y^{^{''}} - 0.2 y^{^{'}} + 0.01 y = 0, y (0) = 10, y^{^{'}} (0) = b

\int cos (30 x) \cdot cos (4 x) \cdot cos (4 x) d x

y^{^{'}} = x + y, y (0) = 10

\frac{\partial}{\partial v} (u (v, w) + v e^{w})

What is (\partial ^2)/(\partial x\partial y)(x^5+x^2y+x+3) ?
The answer to (\partial ^2)/(\partial x\partial y)(x^5+x^2y+x+3) is 2x