What is the derivative of (x^3-8/(x^3+8)) ?

The derivative of (x^3-8/(x^3+8)) is (48x^2)/((x^3+8)^2)

What is the first derivative of (x^3-8/(x^3+8)) ?

The first derivative of (x^3-8/(x^3+8)) is (48x^2)/((x^3+8)^2)

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\frac{d}{d x} (\frac{x ^{3} - 8}{x ^{3} + 8})

\frac{48 x ^{2}}{( x ^{3} + 8 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{3} - 8}{x ^{3} + 8})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{3} - 8 ) ( x ^{3} + 8 ) - \frac{d}{d x} ( x ^{3} + 8 ) ( x ^{3} - 8 )}{( x ^{3} + 8 ) ^{2}}

\frac{d}{d x} (x^{3} - 8) = 3 x^{2}

\frac{d}{d x} (x^{3} + 8) = 3 x^{2}

= \frac{3 x ^{2} ( x ^{3} + 8 ) - 3 x ^{2} ( x ^{3} - 8 )}{( x ^{3} + 8 ) ^{2}}

Expand

3 x^{2} (x^{3} + 8) - 3 x^{2} (x^{3} - 8) : 48 x^{2}

= \frac{48 x ^{2}}{( x ^{3} + 8 ) ^{2}}

\frac{\partial}{\partial x} (x^{2} y - y^{2} - 7)

\int sec^{5} (4 x) tan (4 x) d x

x \to - 1 lim (10 x)

x y + 5 e^{y} = 5 e

\frac{d}{d x} (tan (a x + b))

What is the derivative of (x^3-8/(x^3+8)) ?
The derivative of (x^3-8/(x^3+8)) is (48x^2)/((x^3+8)^2)
What is the first derivative of (x^3-8/(x^3+8)) ?
The first derivative of (x^3-8/(x^3+8)) is (48x^2)/((x^3+8)^2)