What is (\partial)/(\partial y)(e^{-x}sec(y)) ?

The answer to (\partial)/(\partial y)(e^{-x}sec(y)) is e^{-x}sec(y)tan(y)

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(\partial)/(\partial y)(e^{-x}sec(y))

\frac{\partial}{\partial y} (e^{- x} sec (y))

e^{- x} sec (y) tan (y)

Solution steps

\frac{\partial}{\partial y} (e^{- x} sec (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{- x} \frac{\partial}{\partial y} (sec (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sec (y)) = sec (y) tan (y)

= e^{- x} sec (y) tan (y)

\frac{d}{d x} (x^{4} + x)

\frac{d}{d x} (sin^{2} (2 x))

y = - x^{2} + 62

\frac{d}{d x} (\frac{cos ( x )}{cos ( x ) + 1})

What is (\partial)/(\partial y)(e^{-x}sec(y)) ?
The answer to (\partial)/(\partial y)(e^{-x}sec(y)) is e^{-x}sec(y)tan(y)