What is the integral of (8+t+t^2)/(sqrt(t)) ?

The integral of (8+t+t^2)/(sqrt(t)) is 16sqrt(t)+2/3 t^{3/2}+2/5 t^{5/2}+C

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integral of (8+t+t^2)/(sqrt(t))

\int \frac{8 + t + t ^{2}}{t} d t

16 t + \frac{2}{3} t^{\frac{3}{2}} + \frac{2}{5} t^{\frac{5}{2}} + C

Solution steps

\int \frac{8 + t + t ^{2}}{t} d t

Expand

\frac{8 + t + t ^{2}}{t} : \frac{8}{t} + t + t^{\frac{3}{2}}

= \int \frac{8}{t} + t + t^{\frac{3}{2}} d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{8}{t} d t + \int t d t + \int t^{\frac{3}{2}} d t

\int \frac{8}{t} d t = 16 t

\int t d t = \frac{2}{3} t^{\frac{3}{2}}

\int t^{\frac{3}{2}} d t = \frac{2}{5} t^{\frac{5}{2}}

= 16 t + \frac{2}{3} t^{\frac{3}{2}} + \frac{2}{5} t^{\frac{5}{2}}

Add a constant to the solution

= 16 t + \frac{2}{3} t^{\frac{3}{2}} + \frac{2}{5} t^{\frac{5}{2}} + C

\int e^{3 x} d x

8 x^{2} + 3 x

\frac{d}{d x} (2 c x + c^{2})

f (x) = 2 x^{2} - x^{3}

(2 t - 1) (4 t - 6)^{- 1}

What is the integral of (8+t+t^2)/(sqrt(t)) ?
The integral of (8+t+t^2)/(sqrt(t)) is 16sqrt(t)+2/3 t^{3/2}+2/5 t^{5/2}+C