What is the derivative of f(x)=2x^2-x^3 ?

The derivative of f(x)=2x^2-x^3 is 4x-3x^2

What is the first derivative of f(x)=2x^2-x^3 ?

The first derivative of f(x)=2x^2-x^3 is 4x-3x^2

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derivative of

f (x) = 2 x^{2} - x^{3}

4 x - 3 x^{2}

Solution steps

\frac{d}{d x} (2 x^{2} - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 4 x - 3 x^{2}

(2 t - 1) (4 t - 6)^{- 1}

x^{2} y^{^{''}} - 2 y = 0, y (1) = 0, y^{^{'}} (1) = 3

x \to + 0 lim (x^{8} - \frac{1}{x})

x \to 1 - lim (\frac{x - 1}{∣ x - 1 ∣})

\int - x sin (y) + 2 y d y

What is the derivative of f(x)=2x^2-x^3 ?
The derivative of f(x)=2x^2-x^3 is 4x-3x^2
What is the first derivative of f(x)=2x^2-x^3 ?
The first derivative of f(x)=2x^2-x^3 is 4x-3x^2