What is (\partial)/(\partial x)(rcos(x)sin(y)) ?

The answer to (\partial)/(\partial x)(rcos(x)sin(y)) is -rsin(x)sin(y)

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(\partial)/(\partial x)(rcos(x)sin(y))

\frac{\partial}{\partial x} (r cos (x) sin (y))

- r sin (x) sin (y)

Solution steps

\frac{\partial}{\partial x} (r cos (x) sin (y))

Treat

r, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r sin (y) \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= r sin (y) (- sin (x))

Simplify

= - r sin (x) sin (y)

\frac{d y}{d t} = k y (1 - \frac{y}{4600})

f (x) = 8 sin (x), g (x) = 8 cos (2 x)

f (x) = \frac{1}{6} (2 x + 1)^{3}

\int \frac{( x ^{5} - x ^{3} + 6 x )}{x ^{4}} d x

x^{3} - 11 x^{2} + 30 x, - x^{3} + 11 x^{2} - 30 x

What is (\partial)/(\partial x)(rcos(x)sin(y)) ?
The answer to (\partial)/(\partial x)(rcos(x)sin(y)) is -rsin(x)sin(y)