What is area y=x,y=2xsqrt(1-x^2) ?

The answer to area y=x,y=2xsqrt(1-x^2) is 5/12

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area y=x,y=2xsqrt(1-x^2)

area

y = x, y = 2 x 1 - x^{2}

\frac{5}{12}

Decimal Notation

0.41666 \dots

Solution steps

Apply the area formula:

\int_{- \frac{3}{2}}^{\frac{3}{2}} x - 2 x 1 - x^{2} d x

Solve

\int_{- \frac{3}{2}}^{\frac{3}{2}} x - 2 x 1 - x^{2} d x : \frac{5}{12}

The area is:

= \frac{5}{12}

\frac{d}{d x} (e^{x} sin (x^{2}))

\frac{d}{d x} (2 x + sin (2 x))

\frac{\partial}{\partial y} (x e^{7 x y})

\int e^{(x - 1)} d x

\frac{d y}{d x} = y e^{- x^{2}}

What is area y=x,y=2xsqrt(1-x^2) ?
The answer to area y=x,y=2xsqrt(1-x^2) is 5/12