What is the integral of (7^x-sec^2(x)) ?

The integral of (7^x-sec^2(x)) is (7^x)/(ln(7))-tan(x)+C

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integral of (7^x-sec^2(x))

\int (7^{x} - sec^{2} (x)) d x

\frac{7 ^{x}}{ln ( 7 )} - tan (x) + C

Solution steps

\int 7^{x} - sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7^{x} d x - \int sec^{2} (x) d x

\int 7^{x} d x = \frac{7 ^{x}}{ln ( 7 )}

\int sec^{2} (x) d x = tan (x)

= \frac{7 ^{x}}{ln ( 7 )} - tan (x)

Add a constant to the solution

= \frac{7 ^{x}}{ln ( 7 )} - tan (x) + C

y = x + \frac{2}{x}

x \to 5 + lim (x - 5)

\frac{1}{( s + 3 ) ^{3}}

What is the integral of (7^x-sec^2(x)) ?
The integral of (7^x-sec^2(x)) is (7^x)/(ln(7))-tan(x)+C