What is the derivative of f(x)=9x^3-7x ?

The derivative of f(x)=9x^3-7x is 27x^2-7

What is the first derivative of f(x)=9x^3-7x ?

The first derivative of f(x)=9x^3-7x is 27x^2-7

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derivative of

f (x) = 9 x^{3} - 7 x

27 x^{2} - 7

Solution steps

\frac{d}{d x} (9 x^{3} - 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{3}) - \frac{d}{d x} (7 x)

\frac{d}{d x} (9 x^{3}) = 27 x^{2}

\frac{d}{d x} (7 x) = 7

= 27 x^{2} - 7

y^{^{''}} = (y^{^{'}})^{2} + 1

\int + 2 t d t

y = x^{2} - 1, y = - x + 2

\int 2 x^{2} x d x

h \to 0 lim (\frac{1 + h}{h})

What is the derivative of f(x)=9x^3-7x ?
The derivative of f(x)=9x^3-7x is 27x^2-7
What is the first derivative of f(x)=9x^3-7x ?
The first derivative of f(x)=9x^3-7x is 27x^2-7