What is (\partial)/(\partial z)(3xyz^2) ?

The answer to (\partial)/(\partial z)(3xyz^2) is 6xyz

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(\partial)/(\partial z)(3xyz^2)

\frac{\partial}{\partial z} (3 x y z^{2})

6 x yz

Solution steps

\frac{\partial}{\partial z} (3 x y z^{2})

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 x y \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 x y \cdot 2 z^{2 - 1}

Simplify

= 6 x yz

e^{2 x} ln (2 x)

x \to - 2 lim (\frac{8}{x})

\frac{\partial}{\partial x} (ln (4 x - 7 y))

(e^{x^{'}})^{^{'}}

\int - \frac{1}{x} + c d x

What is (\partial)/(\partial z)(3xyz^2) ?
The answer to (\partial)/(\partial z)(3xyz^2) is 6xyz