What is the derivative of (x^2/2+1) ?

The derivative of (x^2/2+1) is x

What is the first derivative of (x^2/2+1) ?

The first derivative of (x^2/2+1) is x

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\frac{d}{d x} (\frac{x ^{2}}{2} + 1)

x

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{2}}{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (\frac{x ^{2}}{2}) = x

\frac{d}{d x} (1) = 0

= x + 0

Simplify

= x

n = 0 \sum \infty \frac{e}{n}

\frac{\partial}{\partial x} (ln (t^{2} + 1))

\frac{d}{d x} (a x^{5} ln (\frac{x}{2}) + b x^{3} (x - 2))

\int \frac{1 + 2 x + x ^{2}}{3 x + 3 x ^{2} + x ^{3}} d x

f (x) = x^{6} ln (x)

What is the derivative of (x^2/2+1) ?
The derivative of (x^2/2+1) is x
What is the first derivative of (x^2/2+1) ?
The first derivative of (x^2/2+1) is x