What is (\partial)/(\partial x)(ln(t^2+1)) ?

The answer to (\partial)/(\partial x)(ln(t^2+1)) is 0

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(\partial)/(\partial x)(ln(t^2+1))

\frac{\partial}{\partial x} (ln (t^{2} + 1))

0

Solution steps

\frac{\partial}{\partial x} (ln (t^{2} + 1))

Treat

t

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\frac{d}{d x} (a x^{5} ln (\frac{x}{2}) + b x^{3} (x - 2))

\int \frac{1 + 2 x + x ^{2}}{3 x + 3 x ^{2} + x ^{3}} d x

f (x) = x^{6} ln (x)

f (x) = - 4 sin (2 x)

t^{2} y^{^{''}} - 3 t y^{^{'}} - 21 y = 0

What is (\partial)/(\partial x)(ln(t^2+1)) ?
The answer to (\partial)/(\partial x)(ln(t^2+1)) is 0