What is the slope ofintercept (-1,2),(1,-1) ?

The slope ofintercept (-1,2),(1,-1) is y=-3/2 x+1/2

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slope ofintercept (-1,2),(1,-1)

slope intercept

(- 1, 2), (1, - 1)

y = - \frac{3}{2} x + \frac{1}{2}

Solution steps

Compute the slope

(- 1, 2), (1, - 1) : m = - \frac{3}{2}

Compute the

y

intercept:

b = \frac{1}{2}

Construct the line equation

y = mx + b

where

m = - \frac{3}{2}

and

b = \frac{1}{2}

y = - \frac{3}{2} x + \frac{1}{2}

\int 2 x^{5} y + 3 x^{4} y^{2} d y

\frac{\partial}{\partial x} (x yz)

\int e^{- 2 x} (1 - 2 x) d x

\frac{d}{d x} (2^{0.25})

\frac{d}{d x} (sin (7 x) + cos (2 x))

What is the slope ofintercept (-1,2),(1,-1) ?
The slope ofintercept (-1,2),(1,-1) is y=-3/2 x+1/2