What is the tangent of y=(2x)/(x-1),(-1,1) ?

The tangent of y=(2x)/(x-1),(-1,1) is y=-1/2 x+1/2

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tangent of y=(2x)/(x-1),(-1,1)

tangent of

y = \frac{2 x}{x - 1}, (- 1, 1)

y = - \frac{1}{2} x + \frac{1}{2}

Solution steps

Find the slope of

y = \frac{2 x}{x - 1} : \frac{d y}{d x} = - \frac{2}{( x - 1 ) ^{2}}

Compute the slope of

y = \frac{2 x}{x - 1}

(- 1, 1) : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(- 1, 1) : y = - \frac{1}{2} x + \frac{1}{2}

y = - \frac{1}{2} x + \frac{1}{2}

\frac{d}{d x} (x^{a x})

\frac{d}{d x} (x x^{2} + 4)

\int (2 x + 2) d x

\frac{\partial}{\partial x} (x^{2} + y^{2} + x + y + x y)

\int 6 x - x^{2} d x

What is the tangent of y=(2x)/(x-1),(-1,1) ?
The tangent of y=(2x)/(x-1),(-1,1) is y=-1/2 x+1/2