What is (\partial)/(\partial x)(x^2+y^2+x+y+xy) ?

The answer to (\partial)/(\partial x)(x^2+y^2+x+y+xy) is 2x+y+1

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(\partial)/(\partial x)(x^2+y^2+x+y+xy)

\frac{\partial}{\partial x} (x^{2} + y^{2} + x + y + x y)

2 x + y + 1

Solution steps

\frac{\partial}{\partial x} (x^{2} + y^{2} + x + y + x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x y) = y

= 2 x + 0 + 1 + 0 + y

Simplify

= 2 x + y + 1

\int 6 x - x^{2} d x

f (x) = (2 x^{3} + 4 x + 1)

\int (4 + 4 tan^{2} (v)) d v

(sin (\frac{x}{2}))^{^{'}}

\frac{\partial}{\partial x} (x y^{2} + y e^{x^{2}} + 5)

What is (\partial)/(\partial x)(x^2+y^2+x+y+xy) ?
The answer to (\partial)/(\partial x)(x^2+y^2+x+y+xy) is 2x+y+1